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Class 10 · Maths NCERT Class 10 Maths · Ch. 44 min read · 15 questions

Quadratic Equations

Maths

Quadratic Equations

A quadratic equation in x is an equation of the form ax2 + bx + c = 0, where a, b, c are real numbers and a is not 0. The word "quadratic" comes from "quadratus" (Latin for square). Quadratic equations arise in problems involving area, projectile motion, and many real-life situations.

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Key Concepts

Standard Form: ax2 + bx + c = 0, a not= 0. The left side is a quadratic polynomial.

Solution (Root): A value of x that satisfies the equation. A quadratic equation has at most two roots.

Methods of Solving:

1. Factorisation: Express ax2 + bx + c as a product of two linear factors. Set each factor to zero.

2. Completing the Square: Rewrite ax2 + bx + c = 0 as (x + p)2 = q, then take square roots.

3. Quadratic Formula: x = (-b ± √(b2 - 4ac)) / (2a)

  • Discriminant (D): D = b2 - 4ac
  • D > 0: Two distinct real roots
  • D = 0: Two equal real roots (one repeated root)
  • D < 0: No real roots (roots are imaginary)

Nature of Roots Summary:
| D | Nature |
|---|--------|
| D > 0 | Real and distinct |
| D = 0 | Real and equal |
| D < 0 | No real roots |

Key formulas

Relationship between Roots: If alpha and beta are roots of ax2 + bx + c = 0:
alpha + beta = -b/a
alpha x beta = c/a

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Worked Examples

Example 1

Solve x2 - 5x + 6 = 0 by factorisation.
We need two numbers whose product is 6 and sum is -5: -2 and -3.
x2 - 5x + 6 = (x - 2)(x - 3) = 0.
Roots: x = 2 and x = 3.

Example 2

Solve 2x2 - 5x + 3 = 0 by factorisation.
Product = 2 x 3 = 6; we need numbers summing to -5: -2 and -3.
2x2 - 2x - 3x + 3 = 2x(x - 1) - 3(x - 1) = (2x - 3)(x - 1) = 0.
Roots: x = 3/2 and x = 1.

Example 3

Solve x2 + 4x - 5 = 0 by completing the square.
x2 + 4x = 5.
Add (4/2)2 = 4 to both sides: x2 + 4x + 4 = 9.
(x + 2)2 = 9. x + 2 = ±3.
x = 1 or x = -5.

Example 4

Solve 3x2 - 5x + 2 = 0 using the quadratic formula.
a = 3, b = -5, c = 2. D = 25 - 24 = 1.
x = (5 ± 1) / 6. x = 1 or x = 2/3.
Roots: x = 1 and x = 2/3.

Example 5

Find the discriminant and nature of roots of x2 + x + 1 = 0.
D = 12 - 4(1)(1) = 1 - 4 = -3. D < 0. No real roots.

Example 6

A train travels 360 km at a uniform speed. If the speed were 5 km/h more, it would take 1 hour less. Find the speed.
Let speed = x km/h. Time = 360/x hours.
New time = 360/(x+5) hours. Difference = 1 h:
360/x - 360/(x+5) = 1.
360(x+5) - 360x = x(x+5).
1800 = x2 + 5x.
x2 + 5x - 1800 = 0.
(x + 45)(x - 40) = 0. x = 40 (taking positive value).
Speed = 40 km/h.

Example 7

For what value of k does kx2 + 2x + 1 = 0 have equal roots?
For equal roots, D = 0: 4 - 4k = 0, so k = 1.

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Key Formulas

Key formulas

Quadratic formula: x = (-b ± √(b2 - 4ac)) / 2a
Discriminant: D = b2 - 4ac
Sum of roots: alpha + beta = -b/a
Product of roots: alpha x beta = c/a

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Common mistakes

  • Forgetting that a quadratic equation must have a = not 0. If a = 0, it becomes linear.
  • Taking only the positive square root in completing the square — always write ± .
  • Using D to check nature of roots but then forgetting that D < 0 means no real roots, not "no roots."

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Summary

Quadratic equations are solved by factorisation, completing the square, or the formula. The discriminant is a quick indicator of the nature of roots without fully solving the equation. These skills are foundational for higher algebra and calculus.

Practice Problems

15 questions with instant feedback.

Question 1 of 15Score 0

Which of the following is a quadratic equation?