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Class 11 · Mathematics NCERT Class 11 Mathematics · Ch. 43 min read · 15 questions

Complex Numbers and Quadratic Equations

Mathematics

Complex Numbers and Quadratic Equations

The real number system is insufficient to solve equations like x2 + 1 = 0. By introducing the imaginary unit i, where i2 = -1, we extend real numbers to complex numbers, unlocking solutions to all polynomial equations.

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Complex Numbers

Key formulas

A complex number is z = a + ib, where a, b ∈ R.
a = Re(z) is the real part.
b = Im(z) is the imaginary part.
When b = 0, z is real. When a = 0, z is purely imaginary.

Equality: a + ib = c + id if and only if a = c and b = d.

  • Powers of i:
  • i1 = i, i2 = −1, i3 = −i, i4 = 1 (cycle of period 4)

To find in: divide n by 4; use the remainder.

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Operations

Addition: (a + ib) + (c + id) = (a+c) + i(b+d)
Subtraction: (a + ib) − (c + id) = (a−c) + i(b−d)
Multiplication: (a + ib)(c + id) = (ac − bd) + i(ad + bc)
Division: (a+ib)/(c+id) = [(a+ib)(c−id)] / (c2+d2)

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Modulus and Conjugate

Key formulas

Conjugate of z = a + ib is z-bar = a − ib.
Modulus of z is |z| = √(a2 + b2).
z · z-bar = |z|2 (used in division).

Key properties: |z1 · z2| = |z1| · |z2|; |z1/z2| = |z1|/|z2|.

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Argand Plane

A complex number a + ib is represented by the point (a, b) on the Argand plane (complex plane). The argument (or angle) θ satisfies tan θ = b/a.

Polar form: z = r(cos θ + i sin θ), where r = |z| and θ = arg(z).

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Quadratic Equations

  • For a quadratic ax2 + bx + c = 0 (a ≠ 0), the discriminant is D = b2 − 4ac.
  • D > 0: Two distinct real roots.
  • D = 0: Two equal real roots (x = −b/2a).
  • D < 0: Two complex conjugate roots x = (−b ± i·√(|D|)) / 2a.

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Worked Examples

Example 1

Compute i35.
35 = 4×8 + 3, so i35 = i3 = −i.

Example 2

Express (3 + 2i)(1 − i) in a + ib form.
= 3 − 3i + 2i − 2i2 = 3 − i + 2 = 5 − i.

Example 3

Find |3 − 4i|.
|3 − 4i| = √(9 + 16) = √(25) = 5.

Example 4

Write 1/(2 + 3i) in a + ib form.
Multiply numerator and denominator by the conjugate (2 − 3i): (2−3i)/(4+9) = 2/13 − 3i/13.

Example 5

Find the conjugate of (2 + 3i)/(1 − i).
First simplify: (2+3i)(1+i)/((1)2+(1)2) = (2+2i+3i+3i2)/2 = (2+5i−3)/2 = (−1+5i)/2. Conjugate = (−1−5i)/2.

Example 6

Solve x2 + 4 = 0 over C.
x2 = −4, so x = ±2i.

Example 7

Solve x2 − 4x + 13 = 0.
D = 16 − 52 = −36. x = (4 ± √(−36))/2 = (4 ± 6i)/2 = 2 ± 3i.

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Common mistakes

  • Forgetting i2 = −1 during multiplication (writing i2 = 1 is a common error).
  • Not multiplying by the conjugate correctly when simplifying a/z.
  • Confusing the modulus |z| with the imaginary part Im(z).

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Summary

Complex numbers extend real numbers by introducing i. All standard algebraic operations apply. Every quadratic equation has solutions in C. The Argand plane gives a geometric interpretation.

Practice Problems

15 questions with instant feedback.

Question 1 of 15Score 0

The value of i53 is: