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Class 12 · Physics NCERT Class 12 Physics · Ch. 45 min read · 15 questions

Moving Charges and Magnetism

Physics

Moving Charges and Magnetism

Magnetic fields are produced by moving electric charges (currents). Unlike electric fields that emanate from static charges, magnetic fields arise only when charges are in motion.

Key Concepts

  • Magnetic Force on a moving charge (Lorentz Force): F = q(v × B). Magnitude: F = qvB sin(theta), where theta is the angle between v and B. The force is perpendicular to both v and B.
  • No work by magnetic force: The magnetic force is always perpendicular to velocity, so it does no work and does not change kinetic energy — it only changes direction.
  • Circular motion in magnetic field: When v is perpendicular to B, the particle moves in a circle. Radius r = mv / (qB). Time period T = 2 pi m / (qB) — independent of speed!
  • Biot-Savart Law: The magnetic field dB at a point due to a small current element I dl is: dB = (µ0 / 4 pi) × (I dl × rhat) / r2. Here µ0 = 4 pi × 10-7 T·m/A.
  • Magnetic field at centre of circular loop: B = µ0 I / (2R).
  • Ampere's Circuital Law: The line integral of B around any closed path equals µ0 times the total current enclosed. Integral(B · dl) = µ0 Ienclosed.
  • Magnetic field of a long straight wire: B = µ0 I / (2 pi r), directed tangentially (right-hand rule).
  • Solenoid: A long cylindrical coil of N turns per unit length. The field inside: B = µ0 n I (n = turns per unit length). Field outside is nearly zero.
  • Toroid: A solenoid bent into a closed ring. B inside = µ0 n I; B outside = 0.
  • Force on current-carrying conductor in B field: F = IL × B. Magnitude: F = BIL sin(theta).
  • Force between two parallel wires: F/L = µ0 I1 I2 / (2 pi d). Parallel currents attract; antiparallel currents repel.
  • Torque on a current loop: tau = NIAB sin(theta) = m × B, where m = NIA is the magnetic dipole moment.
  • Galvanometer: Uses the torque on a current loop. Converted to ammeter (low shunt in parallel) or voltmeter (high resistance in series).
  • Key Formulas
  • F = qvB sin(theta); r = mv/(qB)
  • Bwire = µ0 I / (2 pi r)
  • Bsolenoid = µ0 n I
  • Torque tau = NIAB sin(theta)
  • m = NIA

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Example 1

An electron moves at 106 m/s perpendicular to a field B = 0.1 T. Find the radius of its circular path.
r = mv/(qB) = (9.1 × 10-31 × 106) / (1.6 × 10-19 × 0.1) = 9.1 × 10-25 / 1.6 × 10-20 = 5.69 × 10-5 m ≈ 0.057 mm

Example 2

Find the magnetic field 0.05 m from a long straight wire carrying 5 A.
B = µ0 I / (2 pi r) = (4 pi × 10-7 × 5) / (2 pi × 0.05) = (2 × 10-6) / (0.1) = 2 × 10-5 T

Example 3

A circular loop of radius 0.1 m carries a current of 2 A. Find B at the centre.
B = µ0 I / (2R) = (4 pi × 10-7 × 2) / (2 × 0.1) = 8 pi × 10-7 / 0.2 = 4 pi × 10-6 ≈ 1.26 × 10-5 T

Example 4

A solenoid has 1000 turns per metre and carries 2 A. Find B inside.
B = µ0 n I = 4 pi × 10-7 × 1000 × 2 = 8 pi × 10-4 ≈ 2.51 × 10-3 T

Example 5

A rectangular loop of dimensions 0.2 m × 0.1 m with 50 turns carries 1 A in a field B = 0.5 T. Find the maximum torque.
taumax = NIAB = 50 × 1 × (0.2 × 0.1) × 0.5 = 50 × 0.01 × 0.5 = 0.25 N·m

Example 6

Two long parallel wires 0.2 m apart carry currents of 3 A and 5 A in the same direction. Find the force per unit length between them.
F/L = µ0 I1 I2 / (2 pi d) = (4 pi × 10-7 × 3 × 5) / (2 pi × 0.2) = (6 × 10-6) / 0.4 = 1.5 × 10-5 N/m (attractive)

Example 7

A galvanometer with coil resistance 50 Omega and full-scale deflection at 1 mA is to be converted to a 5 A ammeter. Find the shunt resistance.
Shunt S = Ig × G / (I - Ig) = 0.001 × 50 / (5 - 0.001) ≈ 0.05 / 5 = 0.01 Omega

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Common mistakes

  • Forgetting that the magnetic force does no work — it cannot change kinetic energy.
  • Using sin(theta) vs cos(theta): force F = qvB sin(theta); torque tau = NIAB sin(theta) — both use sine of the angle with B.
  • Confusing the direction of force: use the right-hand rule (or the thumb, index, middle finger method) carefully.

Summary

Moving charges create magnetic fields and also experience forces in magnetic fields. The Biot-Savart Law and Ampere's Law help calculate B for various current configurations. The torque on current loops is the basis of galvanometers and motors.

Practice Problems

15 questions with instant feedback.

Question 1 of 15Score 0

The force on a charged particle moving parallel to a magnetic field is: