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Class 9 · Maths NCERT Class 9 Maths · Ch. 103 min read · 15 questions

Heron's Formula

Maths

Heron's Formula

Heron's Formula allows us to find the area of a triangle when all three sides are known, without needing the height.

Formula: If a triangle has sides a, b and c, and the semi-perimeter s = (a + b + c)/2, then:
Area = root(s(s-a)(s-b)(s-c))

This formula was developed by the ancient Greek mathematician Heron of Alexandria.

Area using base and height (for reference): Area = (1/2) x base x height.

Area of a quadrilateral using Heron's Formula: Divide the quadrilateral into two triangles by a diagonal, find the area of each triangle using Heron's Formula, and add them.

Example 1

Find the area of a triangle with sides 3, 4 and 5 cm.
s = (3+4+5)/2 = 6.
Area = root(6 x 3 x 2 x 1) = root(36) = 6 sq cm.
(This is also a right triangle: area = (1/2) x 3 x 4 = 6. Confirmed.)

Example 2

A triangle has sides 7, 8 and 9 cm. Find its area.
s = (7+8+9)/2 = 12.
Area = root(12 x 5 x 4 x 3) = root(720) = 12 · root(5) approximately 26.83 sq cm.

Example 3

An equilateral triangle has side 6 cm. Find area using Heron's Formula.
s = (6+6+6)/2 = 9.
Area = root(9 x 3 x 3 x 3) = root(243) = 9 · root(3) approximately 15.59 sq cm.
(Check: formula for equilateral = (root(3)/4) x 36 = 9 · root(3). Confirmed.)

Example 4

A triangular park has sides 40 m, 32 m and 24 m. Find its area.
s = (40+32+24)/2 = 48.
Area = root(48 x 8 x 16 x 24) = root(147456) = 384 sq m.
(Note: 48 x 8 = 384, 16 x 24 = 384. 384 x 384 = 147456. root(147456) = 384.)

Example 5

A rhombus has side 13 cm and one diagonal 10 cm. Find its area.
The diagonal divides the rhombus into two triangles. Each triangle has sides 13, 13 and 10.
s = (13+13+10)/2 = 18.
Area of one triangle = root(18 x 5 x 5 x 8) = root(3600) = 60 sq cm.
Total area = 2 x 60 = 120 sq cm.

Example 6

A quadrilateral ABCD has diagonal AC = 20 m. Triangles ABC and ACD have areas found using Heron's Formula. If both triangles have the same area of 150 sq m, the quadrilateral area = 300 sq m.

Example 7

Sides of a triangle are in ratio 3:5:7 and perimeter = 300 cm. Find the area.
Sides: 3k + 5k + 7k = 300, k = 20. Sides: 60, 100, 140 cm.
s = 150.
Area = root(150 x 90 x 50 x 10) = root(6750000) = 1500 · root(3) approximately 2598 sq cm.

  • Key Formula Summary:
  • s = (a + b + c) / 2
  • Area = root(s(s-a)(s-b)(s-c))
  • Equilateral triangle area = (root(3)/4) x a2

Common mistakes

Students forget to divide the perimeter by 2 when finding s. Also, all three sides must satisfy the triangle inequality before applying the formula. If the product s(s-a)(s-b)(s-c) is negative, the given sides do not form a triangle.

Summary

Heron's Formula is a universal method for triangle area using only the three side lengths. It is especially useful when the height is not given. Divide quadrilaterals into triangles to extend the method.

Practice Problems

15 questions with instant feedback.

Question 1 of 15Score 0

In Heron's Formula, the semi-perimeter s of a triangle with sides a, b, c is: