Unit 2: Electrochemistry
Introduction
Electrochemistry deals with the relationship between chemical energy and electrical energy — specifically how chemical reactions produce electricity and how electricity drives chemical reactions. It underpins batteries, fuel cells, electroplating, and corrosion.
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Electrochemical Cells
- An electrochemical cell converts chemical energy into electrical energy (or vice versa). Two main types:
- Galvanic (Voltaic) cell: Spontaneous redox reaction generates electricity (e.g., Daniel cell)
- Electrolytic cell: Electrical energy drives a non-spontaneous chemical reaction (e.g., electrolysis of water)
- Daniel Cell: Zn rod in ZnSO4 solution (anode) and Cu rod in CuSO4 solution (cathode), connected by a salt bridge.
- At anode (oxidation): Zn → Zn2+ + 2e-
- At cathode (reduction): Cu2+ + 2e- → Cu
- Salt bridge maintains electrical neutrality by allowing ion migration.
Cell notation (cell representation):
Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s)
(Single line = phase boundary; Double line = salt bridge)
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Standard Electrode Potential
The Standard Electrode Potential (E°) is the potential of a half-cell under standard conditions (1 M concentration, 298 K, 1 bar pressure) relative to the Standard Hydrogen Electrode (SHE), which is assigned E° = 0.00 V.
- Reduction potential: tendency of a species to be reduced. Higher value = stronger oxidising agent.
- EMF of cell = E°cathode - E°anode (both written as reduction potentials)
- Spontaneous reaction: E°cell > 0 (corresponds to negative delta G)
Relationship: delta G° = -nFE°cell (F = Faraday constant = 96500 C/mol)
delta G° = -RT ln K (equilibrium constant)
So: E°cell = (RT/nF) ln K = (0.0591/n) log K at 298 K
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Nernst Equation
For a cell not at standard conditions:
Ecell = E°cell - (RT/nF) ln Q
At 298 K: Ecell = E°cell - (0.0591/n) log Q
where Q is the reaction quotient.
At equilibrium, Ecell = 0, and Q = K.
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Conductance and Resistivity
Resistance (R): Measured in ohm (Omega). R = rho x l/A (rho = resistivity)
Conductance (G): G = 1/R, unit = siemens (S)
Conductivity (kappa): kappa = 1/rho = G x (l/A). Unit: S m-1
Cell constant: l/A
Molar conductivity (Lambdam): Conductance of solution containing 1 mol of electrolyte, between electrodes 1 unit apart.
Lambdam = kappa x 1000 / M (when kappa in S/cm and M in mol/L)
Kohlrausch's Law: At infinite dilution, the molar conductivity of an electrolyte is the sum of contributions of cation and anion:
Lambdam° = v+ x lambda°_+ + v- x lambda°_-
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Electrolysis and Faraday's Laws
Electrolysis is the decomposition of an electrolyte by passing electric current.
Faraday's First Law: Mass of substance deposited/liberated is directly proportional to the quantity of electricity passed.
m = Z x Q = Z x I x t (Z = electrochemical equivalent)
Faraday's Second Law: When the same quantity of electricity is passed through different electrolytes, the masses deposited are proportional to their equivalent masses.
m proportional to E (equivalent weight)
1 Faraday = 96500 C = charge on 1 mol of electrons.
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Batteries and Fuel Cells
- Primary batteries: Non-rechargeable (e.g., dry cell — Leclanche cell, mercury cell)
- Secondary batteries: Rechargeable (e.g., lead-acid battery, nickel-cadmium, lithium-ion)
- Lead-acid battery: E = 2V per cell, 6 cells = 12V. Anode: Pb; Cathode: PbO2; Electrolyte: H2SO4
- Fuel cells: Produce electricity from continuous supply of fuel (H2) and oxidant (O2). Used in space shuttles. Reactants not stored inside; they are fed continuously.
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Corrosion
Corrosion is the deterioration of a metal due to attack by environmental agents (water, oxygen, acids). Rusting of iron is an electrochemical process:
Anode (oxidation): Fe → Fe2+ + 2e-
Cathode (reduction): O2 + H2O + 4e- → 4OH-
Fe2+ + 2OH- → Fe(OH)2 → Fe2O3.xH2O (rust)
Prevention: Galvanisation (zinc coating), alloying, cathodic protection, painting.
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Worked Examples
Calculate EMF of Daniel cell. E°(Zn2+/Zn) = -0.76 V; E°(Cu2+/Cu) = +0.34 V.
E°cell = E°cathode - E°anode = 0.34 - (-0.76) = +1.10 V
Calculate delta G° for the Daniel cell.
n = 2; F = 96500 C/mol
delta G° = -nFE°cell = -2 x 96500 x 1.10 = -212300 J = -212.3 kJ
Calculate equilibrium constant for Daniel cell reaction at 298 K.
log K = nE°cell / 0.0591 = 2 x 1.10 / 0.0591 = 37.23
K = 1037.23 ≈ 1.7 x 1037
Calculate EMF using Nernst equation for Zn|Zn2+(0.001M)||Cu2+(0.1M)|Cu.
Ecell = 1.10 - (0.0591/2) log(0.001/0.1)
= 1.10 - (0.02955) x log(0.01)
= 1.10 - 0.02955 x (-2) = 1.10 + 0.0591 = 1.159 V
Calculate mass of copper deposited when 0.5 A flows for 2 hours through CuSO4 solution. (Cu atomic mass = 63.5, n = 2)
Q = I x t = 0.5 x 2 x 3600 = 3600 C
Moles of electrons = 3600/96500 = 0.03731 mol
Moles of Cu = 0.03731/2 = 0.01865 mol
Mass = 0.01865 x 63.5 = 1.18 g
The molar conductivity of 0.025 M CH3COOH is 48.15 S cm2 mol-1. Lambda° = 390.5 S cm2 mol-1. Find degree of dissociation.
alpha = Lambdam / Lambdam° = 48.15/390.5 = 0.1233 or 12.33%
Using Kohlrausch law, find Lambda°m for acetic acid if Lambda°m(HCl) = 426.2, Lambda°m(CH3COONa) = 91.0, Lambda°m(NaCl) = 126.4 S cm2 mol-1.
Lambda°m(CH3COOH) = Lambda°(H+) + Lambda°(CH3COO-)
= [Lambda°(HCl) + Lambda°(CH3COONa) - Lambda°(NaCl)]
= 426.2 + 91.0 - 126.4 = 390.8 S cm2 mol-1
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Common mistakes
> - Forgetting that EMF = E°cathode - E°anode (using reduction potentials for both). Never subtract oxidation potential.
> - Confusing molar conductivity with conductivity. Molar conductivity increases with dilution for weak electrolytes; strong electrolytes show a smaller increase.
> - In Faraday's law calculations, always compute moles of electrons and account for the valence (n factor) of the ion.
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Summary
Electrochemistry links electrical and chemical energy. Galvanic cells generate EMF from spontaneous redox reactions; electrolytic cells use electrical energy for non-spontaneous reactions. EMF is calculated from standard electrode potentials; the Nernst equation gives EMF under non-standard conditions. Conductivity concepts and Kohlrausch's law help study electrolytes. Faradays laws quantify electrolysis. Batteries, fuel cells, and corrosion are major applications.