CBSETest.comby Bimal Publications

Need help with Haloalkanes and Haloarenes?

Practice Tests
Class 12 · Chemistry NCERT Class 12 Chemistry · Ch. 64 min read · 15 questions

Haloalkanes and Haloarenes

Chemistry

Haloalkanes and Haloarenes

Haloalkanes (alkyl halides) are derived from alkanes by replacing one or more H atoms with halogens (F, Cl, Br, I). Haloarenes have halogen directly on a benzene ring. These are key industrial solvents, refrigerants, and synthetic building blocks.

Classification

  • By substitution class: Primary (1°) — halogen on C bonded to one C; Secondary (2°) — two C; Tertiary (3°) — three C.
  • By hybridisation: Alkyl halides (sp3 C–X, reactive); vinyl/aryl halides (sp2 C–X, less reactive due to resonance).

Nature of C–X Bond

The C–X bond is polar covalent (X is more electronegative). Bond polarity: C–F > C–Cl > C–Br > C–I. Bond strength decreases and bond length increases from F to I. Reactivity order: RI > RBr > RCl > RF.

Methods of Preparation

  1. 1.From alcohols: ROH + SOCl2 → RCl + SO2 + HCl (no rearrangement)
  2. 2.From alkenes (Markovnikov): CH3CH=CH2 + HBr → CH3CHBrCH3
  3. 3.Finkelstein reaction: RI + NaCl -(acetone)→ RCl + NaI (halogen exchange)
  4. 4.Sandmeyer (aryl halides): ArN2^+Cl^- + CuCl → ArCl + N2

Key Reactions

  • Nucleophilic Substitution:
  • SN2: One-step backside attack, rate = k[RX][Nu^-], inversion of configuration (Walden inversion). Favoured by 1° halides and polar aprotic solvents (DMSO).
  • SN1: Two-step via carbocation, rate = k[RX], racemisation. Favoured by 3° halides and polar protic solvents.

Elimination: Alcoholic KOH + 2° or 3° halides → alkenes (Saytzeff rule: more substituted alkene major).
Grignard reagent: RX + Mg -(dry ether)→ RMgX (nucleophilic carbon, key synthetic tool).
Wurtz reaction: 2RX + 2Na → R–R + 2NaX.

Aryl halides are far less reactive toward SN because the C–X bond has partial double-bond character (resonance). Electron-withdrawing groups (–NO2) at ortho/para activate them.

Worked Examples

Example 1

IUPAC name of CH3–CHBr–CH2–CH3.
Step 1: Longest chain = 4C (butane). Step 2: Br at C-2.
Answer: 2-bromobutane.

Example 2

Why does SN2 give inversion of configuration?
The nucleophile attacks from the back of the C–X bond; the three remaining groups flip (umbrella inversion).
Answer: Complete inversion — Walden inversion; product is the opposite enantiomer.

Example 3

SN1 reactivity order: CH3Cl, (CH3)2CHCl, (CH3)3CCl.
SN1 rate depends on carbocation stability: 3° > 2° > 1°.
Answer: CH3Cl < (CH3)2CHCl < (CH3)3CCl.

Example 4

CH3Br + Mg -(dry ether)→ ?
Answer: CH3MgBr (methylmagnesium bromide, Grignard reagent).

Example 5

Sandmeyer preparation of chlorobenzene.
Aniline + NaNO2/HCl (0-5°C) → C6H5N2^+Cl^-; then + CuCl → C6H5Cl + N2.
Answer: Chlorobenzene.

Example 6

Why does C6H5Cl not react with NaOH(aq) at room temperature?
Resonance gives the C–Cl bond partial double bond character; sp2 C is less electrophilic; ring repels nucleophile.
Answer: Aryl halides are inert to ordinary SN reactions.

Example 7

2-Bromobutane + alcoholic KOH → ?
Alcoholic KOH is a strong base, favours E2. Saytzeff rule: more substituted alkene preferred.
Answer: But-2-ene (major), but-1-ene (minor).

Common mistakes

> Watch out: Aqueous KOH → substitution; alcoholic KOH → elimination. Primary halides prefer SN2; tertiary prefer SN1. Aryl halides need EWG (–NO2 at ortho/para) to undergo nucleophilic substitution.

Summary

Haloalkanes react via SN1/SN2 or elimination depending on structure and conditions. Grignard reagents are vital synthetic intermediates. Aryl halides are resistant to SN due to resonance but can undergo electrophilic substitution. Reactivity order: RI > RBr > RCl > RF.

Practice Problems

15 questions with instant feedback.

Question 1 of 15Score 0

Which of the following is a primary alkyl halide?